2x-(2-7x)^2=(1-7x)(1+7x)

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Solution for 2x-(2-7x)^2=(1-7x)(1+7x) equation: 



2x-(2-7x)^2=(1-7x)(1+7x)

We move all terms to the left:

2x-(2-7x)^2-((1-7x)(1+7x))=0

We add all the numbers together, and all the variables

2x-(-7x+2)^2-((-7x+1)(7x+1))=0

We multiply parentheses ..

-((-49x^2-7x+7x+1))+2x-(-7x+2)^2=0



We calculate terms in parentheses: -((-49x^2-7x+7x+1)), so:

(-49x^2-7x+7x+1)

We get rid of parentheses

-49x^2-7x+7x+1

We add all the numbers together, and all the variables

-49x^2+1

Back to the equation:

-(-49x^2+1)



We get rid of parentheses

49x^2+2x-(-7x+2)^2-1=0

We move all terms containing x to the left, all other terms to the right

49x^2+2x-(-7x+2)^2=1

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